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4x^2+132x-65.4375=0
a = 4; b = 132; c = -65.4375;
Δ = b2-4ac
Δ = 1322-4·4·(-65.4375)
Δ = 18471
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(132)-\sqrt{18471}}{2*4}=\frac{-132-\sqrt{18471}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(132)+\sqrt{18471}}{2*4}=\frac{-132+\sqrt{18471}}{8} $
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